2sin^2(3x)=1-cos(5x)

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Solution for 2sin^2(3x)=1-cos(5x) equation:


Simplifying
2sin2(3x) = 1 + -1cos(5x)

Remove parenthesis around (3x)
2in2s * 3x = 1 + -1cos(5x)

Reorder the terms for easier multiplication:
2 * 3in2s * x = 1 + -1cos(5x)

Multiply 2 * 3
6in2s * x = 1 + -1cos(5x)

Multiply in2s * x
6in2sx = 1 + -1cos(5x)

Remove parenthesis around (5x)
6in2sx = 1 + -1cos * 5x

Reorder the terms for easier multiplication:
6in2sx = 1 + -1 * 5cos * x

Multiply -1 * 5
6in2sx = 1 + -5cos * x

Multiply cos * x
6in2sx = 1 + -5cosx

Solving
6in2sx = 1 + -5cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '6n2sx'.
i = 0.1666666667n-2s-1x-1 + -0.8333333333cn-2o

Simplifying
i = 0.1666666667n-2s-1x-1 + -0.8333333333cn-2o

Reorder the terms:
i = -0.8333333333cn-2o + 0.1666666667n-2s-1x-1

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